Posted by **jay** on Monday, November 12, 2012 at 9:50am.

use the remainder theorem to find the remainder when P(x)=x^4-9x^3-5x^2-3x+4 is divided by x+3

- algebra -
**Steve**, Monday, November 12, 2012 at 10:10am
Just plug in x = -3 and the value P(-3) is the remainder when P(x) is divided by (x+3).

- algebra -
**lee**, Monday, November 12, 2012 at 3:09pm
-3[1 -9 -5 -3 4

-3 36 -93 288

1 -12 32 -96 292

x^3-12x^2+31x-96

x+3[x^4-9x^3-5x^2-3x+4

-(x^4+3x^3)

-12x^3-5x^2

-(-12x^3-36^2

31x^2-3x

(-31x^2+93x)

-96x+4

-(-96-288)

292

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