Posted by jay on Monday, November 12, 2012 at 9:50am.
use the remainder theorem to find the remainder when P(x)=x^49x^35x^23x+4 is divided by x+3

algebra  Steve, Monday, November 12, 2012 at 10:10am
Just plug in x = 3 and the value P(3) is the remainder when P(x) is divided by (x+3).

algebra  lee, Monday, November 12, 2012 at 3:09pm
3[1 9 5 3 4
3 36 93 288
1 12 32 96 292
x^312x^2+31x96
x+3[x^49x^35x^23x+4
(x^4+3x^3)
12x^35x^2
(12x^336^2
31x^23x
(31x^2+93x)
96x+4
(96288)
292
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