Posted by **Kara** on Monday, November 12, 2012 at 9:40am.

A dog trainer has 64 ft of fencing that will be used to create a rectangular work area for dogs. If the trainer wants to enclose an area of 192 ft2, what will be the dimensions of the work area?

- Algebra -
**Steve**, Monday, November 12, 2012 at 10:07am
guessing way:

192 = 2^6*3 = 16*12 = 8*24

2(8+24) = 64

so the work area is 8x24

algebraic way:

If the pen's width is w, then the length is 32-w

w(32-w) = 192

w^2 - 32w + 192 = 0

(w-8)(w-24) = 0

w = 8 or 24

so, the pen is 8x24

Unless you use the quadratic formula, factoring the polynomial is essentially the same as guessing the right factors of 192!

## Answer This Question

## Related Questions

- math - a dog owner has 200ft of fencing and wants to enclose the greatest ...
- Algebra 2 - If you have 64 feet of fencing available to create a rectangular pen...
- Algebra - The back of George's property is a creek. George would like to ...
- Math- algebra - using L as the length and W is wide asume L is great then W . If...
- algebra - A man wants to build a rectangular pen in which to keep his dog. If he...
- College Algebra - A rancher wishes to enclose a rectangular partitioned corral ...
- Algebra - The back of Tom's property is a creek. Tom would like to enclose a ...
- Math - 24 m of fencing are available to enclose a play area. what would the ...
- Calculus 1 - If you have 280 meters of fencing and want to enclose a rectangular...
- Math - Eighty metres of fencing are available to enclose a rectangular area. ...

More Related Questions