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posted by TRIG HELP on Monday, November 12, 2012 at 7:31am.
Find one numerical value for cot x/cos x = 5
cotx = 5cosx cosx/sinx - 5cosx = 0 cosx(1/sinx - 5) = 0 cosx = 0 or 1/sinx = 5 if cosx = 0, x = π/2 , 3π/2 if 1/sinx = 5 sinx = 1/5 x = .20136 or 2.94023
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