Post a New Question
posted by Anonymous on Monday, November 12, 2012 at 12:10am.
if the heat of combustion of glucose is -2808 kJ/mol, how many grams of glucose are required to supply 1650 kJ of heat?
2808 kJ/mol = 2808 kJ/180g. So (2808 kJ/180g) x ?g = 1650 kJ. Solve for ?g.
More Related Questions