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January 30, 2015

January 30, 2015

Posted by **nico** on Sunday, November 11, 2012 at 11:23pm.

I know that the derivative of the minute hand is pi/30 rad/min and derivative of the hour hand is pi/360 rad/min.

what is the equation i have to take the derivative of to find dtheta/dt?

- calculus -
**Steve**, Sunday, November 11, 2012 at 11:52pmstarting at t=0 at noon, measured in minutes, the position (with (0,0) at the center of the clock) of the

hour hand is 2cos(2pi/720 t)

min. hand is 3cos(2pi/60 t)

so, the distance d between the hand tips at time t is

d^2 = 2^2 + 3^2 - 2*2*3 cos(pi*t/30 * 119/120)

2d dd/dt = 12(pi/30 * 119/120)sin(pi/30 * 119/120 t)

at 9:20, t=560, so

d = 3.663, so

dd/dt = 1/3.663 * 12(pi/30 * 119/120)sin(pi/30 * 119/120 560)

= 0.34 rad/min

Better check my math. The distance should be shrinking.

I'll try to revisit it later; maybe the above will give you a starting point, and you can fix my error.

- calculus -
**Steve**, Monday, November 12, 2012 at 12:02amI do see one error. The sign of the angle when figuring d:

pi/30 t(1/120 - 1) = -pi/30 t * 119/120, so that will change the sign of the dd/dt, so it is in fact shrinking.

- calculus -
**nico**, Monday, November 12, 2012 at 12:19amin the first line of equation, where did "cos(pi*t/30 * 119/120)" come from?

- calculus -
**Steve**, Monday, November 12, 2012 at 4:05amthe law of cosines uses the angle between the sides, which in our case is the angle between the hour hand and the minute hand.

since the equations are

hour hand is 2cos(2pi/720 t)

min. hand is 3cos(2pi/60 t)

the angle between the hands is

2pi/720 t - 2pi/60 t

= pi/360 t - pi/30 t

= pi/30 t * (1/120 - 1)

= pi/30 t * (-119/120)

- calculus -
**Steve**, Monday, November 12, 2012 at 4:16amoops, that would be pi/30 t (1/12 - 1) = pi/30 t * 11/12

that should change things a bit...

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