posted by Shireen Shaikh on .
A researcher studying the nutritional value of a new candy places a 3.10-gram sample of the candy inside a bomb calorimeter and combusts it in excess oxygen. The observed temperature increase is 2.34 °C. If the heat capacity of the calorimeter is 33.50 kJ·K–1, how many nutritional Calories are there per gram of the candy?
q = Ccal x delta T.
q = 33500 J x 2.34 = about 79,000 J (but you need to do it more accurately).
That's 79000 J/3.10 g = 25,000 J/g.
25,000 J/g x (1 cal/4.184 J) = about 6,000 cal/g or 6 kcal/g = 6 nutritional calories/g.