solve for X
-7=7x^2-10x+6
move the -7 over:
7x^2 - 10x + 13 = 0
using the quadratic formula,
x = (10 +/- sqrt(100-364))/14
= (5 +/- sqrt(66) i)/7
Write the arithmetic sequence 16,20,24,28,in the standard form:
An.....?
To solve the equation -7=7x^2-10x+6 for x, we can start by rearranging the equation to get it in the standard form of a quadratic equation (ax^2 + bx + c = 0):
7x^2 - 10x + 6 + 7 = 0
Next, we combine like terms:
7x^2 - 10x + 13 = 0
Now, we have a quadratic equation in the form ax^2 + bx + c = 0. To solve this type of equation, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
Comparing the equation to our quadratic equation, we have:
a = 7, b = -10, c = 13
Plugging these values into the quadratic formula:
x = (-(-10) ± √((-10)^2 - 4 * 7 * 13)) / (2 * 7)
Simplifying further:
x = (10 ± √(100 - 364)) / 14
x = (10 ± √(-264)) / 14
Since we have a negative value inside the square root, the quadratic equation has no real solutions.