posted by Anonymous on .
how many liters of O2 gas measured at 784mmHg and 25'C are required to completely react with 2.3 mole of Al?
4Al + 3O2 ==> 2Al2O3
mols Al = 2.3 from the problem.
Convert to mols O2 required by using the coefficients in the balanced equation.
Then use PV = nRT and solve for volume in L.