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how many liters of O2 gas measured at 784mmHg and 25'C are required to completely react with 2.3 mole of Al?

  • chemistry -

    4Al + 3O2 ==> 2Al2O3
    mols Al = 2.3 from the problem.
    Convert to mols O2 required by using the coefficients in the balanced equation.
    Then use PV = nRT and solve for volume in L.

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