posted by Anonymous .
A large grinding wheel in the shape of a solid cylinder of radius 0.370m is free to rotate on a frictionless, vertical axle. A constant tangential force of 470 N applied to its edge causes the wheel to have an angular acceleration of 0.800 rad/s2. (a) What is the moment of inertia of the wheel?
F*r = I*alpha
where F is the force, r is the radius, I is the moment of inertia, and alpha is the radial acceleration
470*0.370 = I * 0.8