Posted by **Anonymous** on Sunday, November 11, 2012 at 5:33pm.

A large grinding wheel in the shape of a solid cylinder of radius 0.370m is free to rotate on a frictionless, vertical axle. A constant tangential force of 470 N applied to its edge causes the wheel to have an angular acceleration of 0.800 rad/s2. (a) What is the moment of inertia of the wheel?

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**Jennifer**, Sunday, November 11, 2012 at 7:09pm
F*r = I*alpha

where F is the force, r is the radius, I is the moment of inertia, and alpha is the radial acceleration

470*0.370 = I * 0.8

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**Anonymous**, Thursday, February 25, 2016 at 6:34pm
dgg

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