Balance this chemical equation.
K4Fe(CN)6 + KMnO4 + H2SO4 ---> KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O
10, 122, 299, --> 162, 5, 122, 60, 60, 188
To balance the chemical equation, we need to equalize the number of atoms on both sides of the equation.
The balanced chemical equation is:
2 K4Fe(CN)6 + 10 KMnO4 + 8 H2SO4 ---> 6 KHSO4 + 2 Fe2(SO4)3 + 5 MnSO4 + 10 HNO3 + 6 CO2 + 8 H2O
Here is the step-by-step process:
Step 1: Count the number of atoms for each element on both sides of the equation.
Elements on the left side:
K: 4
Fe: 2
C: 6
N: 6
O: 14
Mn: 1
S: 4
H: 2
Elements on the right side:
K: 7
Fe: 2
S: 4
N: 1
Mn: 1
O: 20
C: 1
H: 11
Step 2: Balance the elements one by one, starting with those that appear in only one compound on each side.
Balance potassium (K):
There are 4 K atoms on the left side and 7 K atoms on the right side.
Multiply K4Fe(CN)6 by 7, giving us 28 K atoms on the left side:
28 K4Fe(CN)6 + 10 KMnO4 + 8 H2SO4 ---> 6 KHSO4 + 2 Fe2(SO4)3 + 5 MnSO4 + 10 HNO3 + 6 CO2 + 8 H2O
Balance iron (Fe):
There are 2 Fe atoms on both sides.
Balance sulfur (S):
There are 4 S atoms on both sides.
Balance nitrogen (N):
There are 6 N atoms on the left side and 1 N atom on the right side.
Multiply HNO3 by 6, giving us 6 N atoms on the right side:
28 K4Fe(CN)6 + 10 KMnO4 + 8 H2SO4 ---> 6 KHSO4 + 2 Fe2(SO4)3 + 5 MnSO4 + 60 HNO3 + 6 CO2 + 8 H2O
Balance oxygen (O):
There are 14 O atoms on the left side and 20 O atoms on the right side.
Add a coefficient of 7 in front of H2O, giving us 14 O atoms on the right side:
28 K4Fe(CN)6 + 10 KMnO4 + 8 H2SO4 ---> 6 KHSO4 + 2 Fe2(SO4)3 + 5 MnSO4 + 60 HNO3 + 6 CO2 + 56 H2O
Balance carbon (C):
There is 1 C atom on the right side.
Add a coefficient of 6 in front of CO2, giving us 6 C atoms on the right side:
28 K4Fe(CN)6 + 10 KMnO4 + 8 H2SO4 ---> 6 KHSO4 + 2 Fe2(SO4)3 + 5 MnSO4 + 60 HNO3 + 36 CO2 + 56 H2O
Balance hydrogen (H):
There are 2 H atoms on the left side and 11 H atoms on the right side.
Add a coefficient of 8 in front of H2O, giving us 16 H atoms on the right side:
28 K4Fe(CN)6 + 10 KMnO4 + 8 H2SO4 ---> 6 KHSO4 + 2 Fe2(SO4)3 + 5 MnSO4 + 60 HNO3 + 36 CO2 + 64 H2O
Step 3: Verify the final balanced equation:
The final balanced equation is:
28 K4Fe(CN)6 + 10 KMnO4 + 8 H2SO4 ---> 6 KHSO4 + 2 Fe2(SO4)3 + 5 MnSO4 + 60 HNO3 + 36 CO2 + 64 H2O
To balance a chemical equation, we need to ensure that the number of atoms of each element is equal on both sides of the equation. Let's balance the given equation step by step:
First, let's start with the potassium (K) atoms. On the left side of the equation, we have 4 potassium atoms from K4Fe(CN)6. To balance the equation, we need to put a coefficient of 2 in front of the product KHSO4, giving us 2 potassium atoms on the right side.
Next, let's balance the manganese (Mn) atoms. On the left side, we have one manganese atom from KMnO4. To balance it on the right side, we need to put a coefficient of 3 in front of MnSO4, giving us 3 manganese atoms.
Now, let's balance the iron (Fe) atoms. On the left side, we have one iron atom from K4Fe(CN)6. To balance it on the right side, we need to put a coefficient of 3 in front of Fe2(SO4)3, giving us 3 iron atoms.
Next, let's balance the carbon (C) atoms. On the left side, we have 6 carbon atoms from K4Fe(CN)6. To balance it on the right side, we need to put a coefficient of 6 in front of CO2, giving us 6 carbon atoms.
Now, let's balance the nitrogen (N) atoms. On the left side, we have 6 nitrogen atoms from K4Fe(CN)6. To balance it on the right side, we need to put a coefficient of 6 in front of HNO3, giving us 6 nitrogen atoms.
Next, let's balance the sulfur (S) atoms. On the left side, we have one sulfur atom from H2SO4. To balance it on the right side, we need to put a coefficient of 3 in front of Fe2(SO4)3 and a coefficient of 2 in front of MnSO4, giving us 3 sulfur atoms on the right side.
Finally, let's balance the hydrogen (H) and oxygen (O) atoms. On the left side, we have 8 hydrogen atoms from H2SO4 and 2 oxygen atoms from KMnO4. On the right side, we have 8 hydrogen atoms from KHSO4, 18 oxygen atoms from Fe2(SO4)3, 4 oxygen atoms from MnSO4, 3 oxygen atoms from HNO3, and 2 oxygen atoms from CO2. To balance these, we need to put a coefficient of 2 in front of H2O, giving us 16 hydrogen atoms and 16 oxygen atoms on the right side.
The balanced chemical equation is:
K4Fe(CN)6 + 2KMnO4 + 3H2SO4 ---> 2KHSO4 + Fe2(SO4)3 + MnSO4 + 3HNO3 + CO2 + 2H2O
You need to learn how to do these yourself. The link below will help do anything you want to do with redox equations and this hint will help you get started.
Fe changes from an oxidation state of +2 (each) on the left to +3(each) on the right. Mn changes from +7 on the left to +2 on the right.
http://www.chemteam.info/Redox/Redox.html