Initially, a particle is moving at 5.30 m/s at an angle of 35.0° above the horizontal (+x axis). Two seconds later, its velocity is 5.97 m/s at an angle of 50.0° below the horizontal. What was the particle's average acceleration during this time interval?

________m/s2 (x component)
________m/s2 (y component)

a=(5.97 @ (-50o)-5.30 @ 35o)/t.

a = ((3.84-4.57i) - (4.34+3.04i))/2

a = (3.84-4.57i -4.34-3.04i)/2

a = (-0.5 - 7.61i)/2

a = -7.63 @ 86.2o/2 = -3.82m/s^2 @ 86.2o

X = -3.82*cos86.2 = -0.253 m/s^2.
Y = -3.82*sin86.2 = -3.81 m/s^2.

To find the particle's average acceleration, we can use the formula for average acceleration:

average acceleration = (change in velocity) / (change in time)

First, we need to find the change in velocity in the x and y components separately.

In the x direction:
Initial velocity = 5.30 m/s
Final velocity = 5.97 m/s * cos(50°) (since it is given as an angle below the horizontal)
change in velocity in the x direction = final velocity - initial velocity

In the y direction:
Initial velocity = 5.30 m/s * sin(35°) (since it is given as an angle above the horizontal)
Final velocity = -5.97 m/s * sin(50°) (since it is given as an angle below the horizontal)
(change in velocity) in the y direction = final velocity - initial velocity

Now, we can calculate the change in time:
Change in time = 2 seconds

Next, we can calculate the average acceleration in each direction:

In the x direction:
average acceleration in the x direction = (change in velocity in the x direction) / (change in time)

In the y direction:
average acceleration in the y direction = (change in velocity in the y direction) / (change in time)

Finally, we can substitute the values and calculate the average accelerations in each direction.