Friday

November 28, 2014

November 28, 2014

Posted by **Bill** on Saturday, November 10, 2012 at 4:32pm.

(b) Answer part A for period from 1918 to present

- Binomial Probability -
**Reiny**, Saturday, November 10, 2012 at 6:50pmProb(male) = .7

prob(female) = .3

a) prob(6 are male_

= C(12,6) (.7)^6 (.3)^6 = .07925

b) prob(6 or more are female)

= prob(6 F) + prob(7 F) + prob(8 F + .. prob(12 F_

=

C(12,6)(.3)^6 (.7)^6 + C(12,7) (.3)^7 (.7)^5 + ... + C(12,12) (.3)^12 (.7)^0

I will let you do the button pushing

prob(less than 4 are female)

= prob(3 F) + prob(2 F) + prob (1 F) + prob(0 F)

= C(12,3) (.3)^3 (.7)^9 + ... + C(12, 0) (.3)^0 (.7)^12

= .....

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