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February 1, 2015

February 1, 2015

Posted by **Kevin** on Saturday, November 10, 2012 at 3:39pm.

- Algebra -
**Jennifer**, Saturday, November 10, 2012 at 6:56pmfc + (11-4)*b = fc + 7*b = 33

fc + (19-4)*b = fc + 15*b = 55

where fc is the fixed charge of the first 4 bushels, and b is the price per bushel of each additional bushel over 4

Use algebra to solve these two equations for b and fc:

fc + 7*b = 33

fc + 15*b = 55

- Algebra -
**Reiny**, Saturday, November 10, 2012 at 7:05pmlet

cost = m(n-4) + b , where n is the number of bushels, b is the extra charge for the first 4 bushels and m is the cost per bushel

so for 11 bushels, cost is 33

33 = 7m + b

so for 19 bushels, cost = 55

55 = 15m + b

subtract them

22 = 8m

m = 22/8 = 2.75

sub into 33 = 7m+b

33 = 19.25 + b

b = 13.75

the fixed cost is $13.75

check:

our equation would be

cost = 2.75(n-4) + 13.75

if n = 11, cost = 2.75(7) + 13.75 = 33

if n=19, cost = 2.75(15) + 13.75 = 55 , YEAH

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