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posted by kelly on Saturday, November 10, 2012 at 2:30pm.
1K2PtCl4+2(NH3)->1Pt(NH3)2Cl2+2KCl what is the percent yield, when 34.5 grams of NH3 react with excess K2PtCl4 if 76.4 g of Pt(NH3)2Cl2 are actually produced?
See your Al2(SO4)3 problem.
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