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October 25, 2014

October 25, 2014

Posted by **Hailey56** on Friday, November 9, 2012 at 9:53pm.

- Physics -
**Jennifer**, Saturday, November 10, 2012 at 12:55pma) The center of mass of the can is halfway up; the center of mass of the soda in the can is also halfway up when the can is full of soda, so the center of mass is

(0.135*(12.4/2) + 1.25*(12.4/2))/(0.135+1.25)

b) After the can loses all the soda, the center of mass is the center of mass of the can, which is halfway up or 12.4/2

c)

x/12.4 is the percentage of soda that has been drained out.

The center of mass of the remaining soda is x/2. The mass of the remaining soda is 1.25*(x/12.4)

Therefore, the COM of the system of the can + soda is:

h = (0.135*(12.4/2) + 1.25*(x/12.4)*(x/2))/(0.135+1.25*(x/12.4)

Graph this function, and see what happens to it as a function of h

d) Evaluate dh/dx = 0

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