Posted by **Cindy** on Friday, November 9, 2012 at 6:47pm.

Find the absolute maximum value and the absolute minimum value, if any, of the following function.

f(x)=1/x^2+2x+8 on [-2,1]

- math -
**Steve**, Friday, November 9, 2012 at 8:19pm
f(-2) = 1/8

f(1) = 1/11

f' = 0 when x = -1

f(-1) = 1/7

f''(-1) < 0, so f(-1) is a max.

So, max = 1/7, min = 1/11

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