Posted by **kela** on Friday, November 9, 2012 at 6:03pm.

Use a linear approximation (or differentials) to estimate the given number.

e0.01

- calculus -
**Steve**, Friday, November 9, 2012 at 6:09pm
y = e^x

y' = e^x

at x=1, y=1

The line through (0,1) with slope=1 is

y = x+1

so, e^0.01 ~ 1+0.01 = 1.01

Note that e^x = 1 + x + 1/2 x^2 + ...

so as a line, e^x ~ 1+x near x=0.

- wow calculus -
**Reiny**, Friday, November 9, 2012 at 6:09pm
Kela, 8 consecutive questions without any indication on your part to show us where your problem is.

Please show us some effort and steps so we can see where you are having problems.

As it stands it looks like a typical case of "homework dumping"

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