Posted by Joey on .
A file cabinet weighing 1500 N is at rest on the floor. The coefficient of static friction between the floor and the cabinet is 0.5. What is the minimum force required to make the file cabinet move horizontally
Fc = 1500 N @ 0o. = Force of cabinet.
Fp = 150*sin(0) = 0 = Force parallel to floor.
Fv = 1500*cos(0) = 1500 N. = Force perpendicular to floor = Normal.
Fs = u*Fv = 0.5*1500 = 750 N. = Force of
Fap-Fp-Fs = m*a.
Fap-0-750 = m*0 = 0
Fap = 750 N. = Force applied.