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Posted by on Friday, November 9, 2012 at 3:07pm.

A box slides downwards at a constant velocity on an inclined surface that has a coefficient of friction uK = .58 The angle of the incline, in degrees, is most nearly:

  • physis - , Friday, November 9, 2012 at 5:25pm

    well, constant velocity, so weight going down = friction force
    mg*sinTheta=mu*mgcosTheta
    tantheta=mu

  • physis - , Sunday, December 30, 2012 at 8:14pm

    [ ì k = tan èk ]

  • physis - , Monday, February 18, 2013 at 1:33pm

    45

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