Posted by **ladybug** on Friday, November 9, 2012 at 1:11pm.

Answer the following function.

f(x)=2x^2-x-1

A. Is the point (-2,9) on the graph of f?

B. If x equals 2, what is fx? What point(S) are on the graph of f?

c. if f(x)= -1, what is x? what point(s) are on the graph of f?

d. what is the domain of f?

e. List the x-intercpts, if any, of the graph of f.

f. List the y-intercept if any, of the graph of f.

**Can someone please help me with this. I have no idea, i'm lost!!!

- college algebra, Please help!! -
**Jennifer**, Friday, November 9, 2012 at 4:56pm
A. is f(-2) = 9? if it is, then the point (-2,9) is on the graph. Otherwise, it's not on the graph

B.Plug 2 into f(x)

f(2) = 2 * (2^2) - 2 - 1

The points on this graph are (2, f(2))

C. Solve

-1 = 2*x^2-x-1

You should find two solutions for x.

D. The domain of f is the range of values for x for which f(x) is real. In this case, the domain is -infinity to infinity

E. Find the solutions when x = 0:

2*0^2 - 0 - 1 = f(x=0)

F. Find the solutions when f(x) = 0

0 = 2*x^2 -x - 1

Solve for the two values of x that make this equation true

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