Posted by **Leslie** on Friday, November 9, 2012 at 7:01am.

An umbrella with a diameter of 1 m turns 22 rev every 44 seconds. If it's 1.5 m from the ground, calculate the time it takes for a drop to reach the ground and the distance away from the umbrella a person should stand so as to not get wet.

For this problem I made a = (0, -g) and used the equation Vyo= 1.5 - g(t^2)/2. And made Vyo=0 so, solving for t, I got sqrt(3/g).

Then v=2pir/T,so (22x2pi)/44s = pi rev/s

so w= pi rev/s

Then, using the equation v=Rw , v = (.5m)(pi rev/s) = pi/2 m/s

After that I didn't know what to do, so if I made any errors above, please let me know. I think for finding the distance I would use the equation D = sqrt(R^2 = Xmax^2) but I don't know how I could incorporate that into the problem

Thank you

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