Posted by **samantha godls** on Thursday, November 8, 2012 at 12:57pm.

Points R=(6,4), Q=(4,3), and P=(-2,b) are collinear. What is the value of b?

- algebra 2 -
**Steve**, Thursday, November 8, 2012 at 2:17pm
the line through R and Q is

(y-4)/(x-6) = (3-4)/(4-6)

or

y = x/2 + 1

so, for (-2,b) to be on the same line,

b = -2/2 + 1 = 0

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