Posted by chemdummy on Thursday, November 8, 2012 at 11:56am.
The easiest way to work the problem is to use the dilution formula of
c1v1 = c2v2
7.5*v1 = 3.00*1.80L
v1 = 3.00*1.80/7.5 = 0.72L or 720 mL of stock. However, do you have a 1.80 L volumetric flask? Probably not. So I would use a 2.0L volumetric flask and
7.5*v1 = 3.00*2
and v1 = about 800 mL. You would measure 800 mL of the stock, add to the 2.0 L volumetric flask, and add water to the mark on the flask.
Related Questions
Chemistry - I can't figure out how to set up this problem...You have a large...
chem - Describe in detail by words how to prepare 200ml of .150M HCl from a 1.00...
Fractions - A technician has prepared three solutions from a 600 mL stock ...
Math - urgent - 2. A technician has prepared three solutions from a 600 mL stock...
Chemistry - What is the molarity of a solution of Mg(OH)2 if the solution ...
Chem - How much water must be added to 500.mL of .200M HCL to produce a .150M ...
Chemistry - You have an unlimited amount of 12M HCl stock solution. You need to ...
Chemistry - You need to find the freezing point of a 1.50m aqueous NaCl solution...
Chemistry Lab - You are given 350 mL a stock solution of 1.66E-02 M benzoic acid...
Chemistry Lab - You are given 350 mL a stock solution of 1.66E-02 M benzoic acid...
For Further Reading
