Friday

February 27, 2015

February 27, 2015

Posted by **Greg Knightly** on Thursday, November 8, 2012 at 8:57am.

A.) What is the magnitude of the speed of the boat relative to a stationary shore observer? Answer in units of m/s.

B.)How far downstream from the initial position is the boat when it reaches the opposite shore? Answer in units of m

- Physics -
**Henry**, Friday, November 9, 2012 at 5:24pmX = 2.81 m/s. = Speed of boat.

Y = -2.39 m/s. = Speed of current.

A. V^2 = X^2 + Y^2

V^2 = (2.81)^2 + (@.39)^2 = 13.61

V = 3.69 m/s.

B. tanA = Y/X = -2.39/2.81 = -0.85053

A = -40.4o = 40.4o South of East.

d = 122*tan(-40.4) = -103.8 m. = 103.8 m

downstream.

- Physics -
**Henry**, Saturday, January 17, 2015 at 9:11pmCorrection:

X = 2.39 m/s = Speed of current.

Y = 2.81m/s = Speed of boat.

B. Tan A = Y/X = 2.81/2.39 = 1.17573

A = 49.6o = 40.4o E. of N.

Tan40.4 = d/122

d = 122*Tan40.4 = 103.8 m. Downstream.

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