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March 30, 2015

March 30, 2015

Posted by **Britney** on Wednesday, November 7, 2012 at 10:23pm.

g(t)=t/t-2 on[4,6]

- math -
**Reiny**, Wednesday, November 7, 2012 at 10:42pmI assume you meant

g(t) = t/(t-2)

g' (t) = ( (t-2)(1) - t(1) )/(t-2)^2

= -2/(t-2)^2

let -2/(-2)^2 = 0 for a max/min

this has no solution,

so the max and mins must occur at the endpoints of your domain

g(4) = 4/(4-2) = 2

g(6) = 6/(6-2) = 6/4 = 3/2

so the max value is 2 and the minimum value is 3/2

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