math
posted by Britney .
Find the absolute maximum value and the absolute minimum value, if any, of the function.
g(t)=t/t2 on[4,6]

I assume you meant
g(t) = t/(t2)
g' (t) = ( (t2)(1)  t(1) )/(t2)^2
= 2/(t2)^2
let 2/(2)^2 = 0 for a max/min
this has no solution,
so the max and mins must occur at the endpoints of your domain
g(4) = 4/(42) = 2
g(6) = 6/(62) = 6/4 = 3/2
so the max value is 2 and the minimum value is 3/2