Posted by **Sara** on Wednesday, November 7, 2012 at 5:57pm.

A random sample of 14 evenings at the O'Sullivan house hold showed that the family received an average of 2.4 solicitation calls each evening. The sample standard deviation was s= 0.9. Find a 99% confidence interval for the population mean number of solicitation calls this family receives each night. Assume that the distribution of the number of solicitation calls this family distribution. Interpret the interval in the context of this problem. State what assumptions were met to use the method you selected.

## Answer This Question

## Related Questions

- Statistics - A random sample of 14 evenings at the O'Sullivan house hold showed ...
- Statistics - 1. A study of 40 people found that they could do on the average15 ...
- probs & stats - 1. A study of 40 people found that they could do on the ...
- Statistics - 1. A study of 40 people found that they could do on the average15 ...
- statistics - A simple random sample of 60 items resulted in a sample mean of 80...
- Statistics (42) - A simple random sample of 60 items resulted in a sample mean ...
- Statistics - In a random sample of 50, the average is 3987 with a population ...
- Statistics - A 95% confidence interval for a population mean, ?, is given as (18...
- Statistics - suppose a random sample of 360 students is drawn form a population ...
- Statistics - Hello, my problem is I have a random sample of only 15 sales ...

More Related Questions