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April 16, 2014

April 16, 2014

Posted by **Anonymous** on Wednesday, November 7, 2012 at 5:24pm.

- d -
**bobpursley**, Wednesday, November 7, 2012 at 5:42pmchange logs to numbers.

1E6(1+-.02)

now, go to logs.

remember that log(ab)=log a+logb

Intensity=6 +log.98 to 6 +log(1.02)

The error is the difference, so

error=log1.02-log.98= .009+.009=.018

You can work it more accurately. Now differentials:

Error=highentensity-lowintensity

dError=dHigh-dlow=log1.02-log.98

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