math
posted by Britney on .
Find the absolute maximum value and the absolute minimum value, if any, of the function. (If an answer does not exist, enter DNE.)
f(x)=x^3+3x^21 on [3,1]

f(3) = 1
f(1) = 3
f'(x) = 3x^2 + 6x = 3x(x+2)
so, there are relative max/min at x= 2,0
f(2) = 3
f(0) = 1
So, on [3,1] we have
min = 1
max = 3