Posted by RJ on .
given the quadratic function f(x)
4x^2 24x +36 find the value of x such that f(x)=4

algebra 
Steve,
just solve
4x^2 24x +36 = 4
4x^2  24x + 32 = 0
x^2  6x + 8 = 0
(x4)(x2) = 0
looks like there are two values for x.