2) Tube (b) is also filled with water, A1 is 0.05m2 and A2 is 0.08m2 Two pistons are placed in both ends of the tube and forces, F1 and F2 are exerted on the pistons so that they remain at the same height. If F1 = 20N what is F2? (I got the answer to this question)
3) Tube (c) is again filled with water. A1 and A2 are the same as in part (b). Two pistons apply different forces to the water in the tube so that the water in the right side of the tube is a height h = 0.43m above the height of the water in the left side of the tube. If F2 = 138 N what is F1?
F1 =
So first you multiply the buoyancy multiplied by gravity times the height. If we have the same problem which we do, the answer for that is 4214 Pa. Then you have to find the pressure in F2. So then do 138/.08= 1725. Then add 1725 and 4214 to get 5939. Multiply by .05.
FINAL ANSWER IS: 296.25!
Just finished it now.
To find F1, we can start by using the principles of Pascal's law, which states that when pressure is applied to an enclosed fluid, the pressure is transmitted uniformly in all directions. In this case, we can use the equation:
F1 / A1 = F2 / A2
Since we know the values of A1 and F2, we can substitute them into the equation:
20N / 0.05m^2 = 138N / 0.08m^2
Now, we need to rearrange the equation to solve for F1:
F1 = (20N / 0.05m^2) * (0.08m^2 / 138N)
Calculating this expression will give us the value of F1.