Posted by **Ashley** on Wednesday, November 7, 2012 at 3:13pm.

A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. The total volume of the solid is 2 cubic centimeters. Find the radius of the cylinder that produces the minimum surface area. (Round your answer to three decimal places.)

- Calculus -
**Steve**, Wednesday, November 7, 2012 at 3:24pm
if the cylinder is of radius r and height h, the volume v is

v = 4/3 pi r^3 + pi r^2 h

so, h = (v - 4/3 pi r^3)/(pi r^2)

h = (2 - 4/3 pi r^3)/(pi r^2)

the surface area a is

a = 4pi r^2 + 2pi r h

= 4pi r^2 + 2pi r (2 - 4/3 pi r^3)/(pi r^2)

= 4pi r^2 + 2/r (2 - 4/3 pi r^3)

= 4pi r^2 + 4/r - 8pi/3 r^2

= (4pi - 8pi/3) r^2 + 4/r

= 4pi/3 r^2 + 4/r

maximum area where da/dr = 0

da/dr = 8pi/3 r - 4/r^2

= (8pi/3 r^3 - 4)/r^2

da/dr=0 when r = ∛(3/2π)

As usual, check my math to verify result.

- Calculus -
**Ashley**, Wednesday, November 7, 2012 at 3:30pm
Is pi in the denominator?

- Calculus -
**Steve**, Wednesday, November 7, 2012 at 3:39pm
yes.

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