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December 22, 2014

December 22, 2014

Posted by **Bash** on Wednesday, November 7, 2012 at 11:31am.

1/1.3 1/2.4 ... 1/n(n 2)

- math - incomplete -
**Steve**, Wednesday, November 7, 2012 at 11:34amI see

n

∑ 1/[n(n+2)]

n=1

but I don' see no steenkin' identity.

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