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Posted by **scott** on Tuesday, November 6, 2012 at 10:57pm.

by pulling on a rope attached to the box. The

student pulls with a force of 173 N at an angle of 27.5 above the horizontal. The box has a

mass of 27 kg, and μk between the box and

the floor is 0.2.

The acceleration of gravity is 9.81 m/s2 .

Find the acceleration of the box.

Answer in units of m/s2

- physics -
**drwls**, Wednesday, November 7, 2012 at 6:37amDivide the net horizontal forward force by the mass.

[173cos27.5 -(M*g -173sin27.5)*ěk]/M = a

M = 27 kg

ěk = 0.2

g = 9.81

Solve for a.

- physics -
**Anonymous**, Thursday, November 6, 2014 at 2:35am-0.232 m/s^2

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