Find the total kinetic energy content of 1.55 moles of an ideal gas at temperature 435 K

http://www.jiskha.com/display.cgi?id=1239240107

To find the total kinetic energy content of a gas, we can use the equation:

Kinetic Energy = (3/2) * n * R * T

Where:
- Kinetic Energy is the total kinetic energy of the gas
- n is the number of moles of the gas
- R is the gas constant (8.314 J/(mol·K))
- T is the temperature in Kelvin

Let's plug in the values to calculate the total kinetic energy:

n = 1.55 moles
R = 8.314 J/(mol·K)
T = 435 K

Kinetic Energy = (3/2) * n * R * T

Kinetic Energy = (3/2) * 1.55 * 8.314 * 435

Now, let's calculate:

Kinetic Energy ≈ 8,840.216 J

Therefore, the total kinetic energy content of 1.55 moles of the ideal gas at a temperature of 435 K is approximately 8,840.216 Joules.