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February 1, 2015

February 1, 2015

Posted by **Mary** on Tuesday, November 6, 2012 at 8:20pm.

are separated by 0.482 m. A 41.1 kg mass is

placed midway between them.

0.482 m

b b

105 kg

41.1 kg

528 kg

Find the magnitude of the net gravitational

force exerted by the two larger masses on the

41.1 kg mass. The value of the universal gravitational constant is 6.672 × 10

−11

N · m2

/kg

2

.

Answer in units of N

Objects with masses of 105 kg and 528 kg

are separated by 0.482 m. A 41.1 kg mass is

placed midway between them.

0.482 m

b b

105 kg

41.1 kg

528 kg

Find the magnitude of the net gravitational

force exerted by the two larger masses on the

41.1 kg mass. The value of the universal gravitational constant is 6.672 × 10

−11

N · m2

/kg

2

- Physics B -
**Elena**, Wednesday, November 7, 2012 at 1:09pmF =G•m1•m2/R²

the gravitational constant G =6.67•10⁻¹¹ N•m²/kg²,

R= 0.241 m

F13= G•m1•m3/R²

F23= G•m2•m3/R²

F23-F13=

=G •m3• (m2-m1)/R²=

=6.67•10⁻¹¹•41.1•(528-105)/0.241²=…

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