top-fuel drag racers are able to uniformly accelerate at 12.9 m/s from rest 97 m/s before crossing the finish line . How much time elapses during the run ?
To find the time elapsed during the run of a top-fuel drag racer, we can use the kinematic equation:
\[ v = u + at \]
where:
- \( v \) is the final velocity,
- \( u \) is the initial velocity,
- \( a \) is the acceleration, and
- \( t \) is the time elapsed.
Given:
- \( u = 0 \) m/s (starting from rest),
- \( v = 97 \) m/s (final velocity),
- \( a = 12.9 \) m/s² (acceleration).
We need to find \( t \).
Rearranging the equation, we have:
\[ t = \frac{{v - u}}{a} \]
Substituting the given values:
\[ t = \frac{{97 - 0}}{12.9} \]
Calculating:
\[ t = 7.519 \] seconds (rounded to three decimal places).
Therefore, the time elapsed during the run of the top-fuel drag racer is approximately 7.519 seconds.