I am less than 100.
The sum of my digits is 8.
If you divide me dy 2,Iam an even number.
My tens digit and my ones digit are the same
Factors of 8
1 + 7
2 + 6
3 + 5
4 + 4
the answer is 44
To solve this problem, we need to find a two-digit number that satisfies the given conditions. Let's go through each condition step by step:
1. "I am less than 100": This means our number should be a two-digit number.
2. "The sum of my digits is 8": The tens and ones digits should add up to 8.
3. "If you divide me by 2, I am an even number": Dividing a number by 2 will give an even number only if the number itself is divisible by 2. So, our number should be even.
4. "My tens digit and my ones digit are the same": The tens digit and ones digit should be equal.
Let's start by finding all possible two-digit numbers where the tens and ones digits are the same:
11, 22, 33, 44, 55, 66, 77, 88, 99
Out of these, let's remove the odd numbers:
11, 33, 55, 77, 99
Finally, let's check which of these satisfy the condition "The sum of my digits is 8":
11: 1 + 1 = 2
33: 3 + 3 = 6
55: 5 + 5 = 10
77: 7 + 7 = 14
99: 9 + 9 = 18
We can see that the only number that satisfies all the given conditions is 88. Therefore, the answer is 88.