Posted by Sarah on .
A 10.0 kg cylinder rolls without slipping on a rough surface. At an instant when its center of gravity has a speed of 16.0 m/s, determine (a) the translational kinetic energy of its center of gravity.(b) the rotational kinetic energy about its center of gravity, and (c) its total kinetic energy.

Physics PLEASE HELP 
Elena,
KE(tr) =m•v²/2,
KE(rot) = I•ω²/2 =m•R²•v²/2•2• R²=m•v²/4.
KE= KE(tr)+ KE(rot)=
=m•v²/2 + m•v²/4= 3• m•v²/4.