Posted by Anonymous on Tuesday, November 6, 2012 at 3:01pm.
Nnewton’s 2 Law for rotation
M = I•ε,
where angular acceleration ε=0.87 rad/s²,
the torque M = F•R ,
the moment of inertia I=mR²/2 ,
F•R= m•R²•ε/2,
m=2•F/R•ε=2•180/0.45•0.87=919.54 kg
I=mR²/2=919.54•0.45²/2=93.1 kg•m².
ω= ε•t=0.87•8=6.96 rad/s
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