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January 26, 2015

January 26, 2015

Posted by **Lindsay** on Tuesday, November 6, 2012 at 1:26pm.

- math -
**Steve**, Tuesday, November 6, 2012 at 2:19pmFirst off, you'd better have A={a,b,c} or the relation R is not over set A.

reflexive: (a,a)? No

Symmetric: (a,b) and (b,a)? No

Transitive: Yes, since

(a,b),(b,c) and (a,c)

(a,b),(b,b)

(a,c),(c,b) and (a,b)

(b,c),(c,b) and (b,b)

(b,c),(c,c)

(c,b),(b,c) and (c,c)

- math -
**sandali**, Monday, November 12, 2012 at 4:45am1235*845

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