Posted by Anonymous on .
The perimeter of a rectangle is 34 ft. The length is 1 ft longer than the width. Find the dimensions. Write a system of linear equation and solve the resulting system. Let x be the length and y be the width.
2x+2y=

a;gebra 
domulus,
2x+2y=34
y+1=x
by substituting x you get
2(y+1)+2y=34
2y+2+2y=34
4y+2=34
4y=32
y=8
y+1=x
x=8+1=9