y=2.12x + 0.004 and Protein A treated w/Bradford Reagent and has an A595 of 0.53. Can you please explain how to calculate this problem so I know in the future? Thanks for your help.
To calculate the protein concentration using the equation y = 2.12x + 0.004, we need to understand what each variable represents:
- y: This variable represents the absorbance value measured at 595 nm (A595).
- x: This variable represents the protein concentration in mg/mL.
In your problem, you are given the absorbance value for Protein A, which is 0.53 (A595). To find the corresponding protein concentration, we need to rearrange the equation:
0.53 = 2.12x + 0.004
Now, let's solve for x:
0.53 - 0.004 = 2.12x
0.526 = 2.12x
To isolate x, divide both sides of the equation by 2.12:
0.526 / 2.12 = x
Calculating this, we find the protein concentration:
x ≈ 0.2481 mg/mL
Therefore, Protein A treated with Bradford Reagent has a protein concentration of approximately 0.2481 mg/mL.