Posted by **Janelle** on Monday, November 5, 2012 at 5:00pm.

A mass of 6.10 kg rests on a smooth surface inclined 39.0o above the horizontal. It is kept from sliding down the plane by a spring attached to the wall. the spring is aligned with the plane and has a spring constant of 126 N/m. How much does the spring stretch?

- Physics -
**Janelle**, Monday, November 5, 2012 at 5:04pm
can you show the steps to how to answer the question as well ? just the steps would be fine :)

- Physics -
**Elena**, Monday, November 5, 2012 at 5:50pm
vector m•a=vector m•g +vector F(spring)

a=0 =>

0=vector m•g +vector F(spring)

x: 0 = m•g•sinα –k•x,

x=m•g•sinα/k=6.1•9.8•sin 39°/126 =0.3 m

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