Homework Help: Calculus

Posted by Matt on Monday, November 5, 2012 at 3:56pm.

A car traveling 132 feet per second decelerates at a constant rate to 60 feet per second in three seconds.
A. what is the negative acceleration?
B. How long after the brakes are first applied will it take to come to a complete stop?
C. How far does it travel before coming to a stop from when the brakes are first applied?

Calculus - Damon, Monday, November 5, 2012 at 4:11pm
change in velocity/change in time = (60-132)/3 = -24 ft/s^2

change in velocity = a t
0 - 132 = -24 t
t = 5.5 seconds to stop

d = Vi t + (1/2) a t^2
= 132(5.5) -.5(24)(5.5)^2
= 426 - 363 = 363 feet

Answer this Question

Related Questions

Calculus - A car traveling at 42 ft/sec decelerates at a constant 7 feet per ...
math - Below is the rule for calculating the velocity of a falling object. Use ...
College Math - The posted speed limit on many U.S. highways is 65 miles per hour...
Calculus - A ladder 15 feet long is leaning against a building so that end X is ...
calculus - At t=0 , a particle starts at the origin with a velocity of 6 feet ...
calculus - A hollow cone has height 5 feet and base diameter 4 feet. The vertex...
Physic Check - These are questions I'm unsure about out of 20 for my ...
Calc - A car traveling at 43 ft/sec decelerates at a constant 5 feet per second ...
Math - If 60 miles per hour is equivalent to a speed of 88 feet per second, ...
College Algebra 1050 - Assume you are on a planet with a gravity constant g (...

For Further Reading

First Name:
School Subject:
Answer: