Liquid water has a specific heat of 4.184 J/g degrees celcius. If 50 grams of water is heated from10 to 55 degrees celcius, what is the heat energy in joules needed to heat this water

To calculate the heat energy needed to heat the water, you can use the formula:

Q = m * c * ΔT

Where:
Q is the heat energy (in joules)
m is the mass of the water (in grams)
c is the specific heat capacity of water (in J/g degrees Celsius)
ΔT is the change in temperature (in degrees Celsius)

Given:
m = 50 grams
c = 4.184 J/g degrees Celsius
ΔT = 55 degrees Celsius - 10 degrees Celsius = 45 degrees Celsius

Substituting the values into the formula:

Q = 50 g * 4.184 J/g degrees Celsius * 45 degrees Celsius
Q = 9382 J

Therefore, the heat energy required to heat the 50 grams of water from 10 to 55 degrees Celsius is 9382 joules.

To find the heat energy needed to heat the water, we can use the formula:

Q = m * c * ΔT

Where:
Q is the heat energy (in joules)
m is the mass of the water (in grams)
c is the specific heat capacity of water (in J/g°C)
ΔT is the change in temperature (in °C)

Given:
m = 50 g
c = 4.184 J/g°C
ΔT = 55°C - 10°C = 45°C

Substituting these values into the formula:

Q = 50 g * 4.184 J/g°C * 45°C

Calculating:

Q = 9390 J

Therefore, the heat energy needed to heat 50 grams of water from 10 to 55 degrees Celsius is 9390 joules.