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October 25, 2014

October 25, 2014

Posted by **Anonymous** on Monday, November 5, 2012 at 11:07am.

- statistics -
**MathGuru**, Monday, November 5, 2012 at 6:17pmUse the normal approximation to the binomial distribution.

Mean = np = 128 * .40 = 51.2

Standard deviation = √npq = √(128 * .40 * .60) = √30.72 = 5.54

Note: q = 1 - p

Formula for z-scores:

z = (x - mean)/sd

With your data:

z = (45 - 51.2)/5.54 = -1.12

Look at a z-table for the probability using the z-score.

Double check my calculations.

I hope this will help.

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