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December 21, 2014

December 21, 2014

Posted by **John** on Monday, November 5, 2012 at 9:52am.

.5, .0303

.249, .0009

.249, .017

.251, .0303

.249, .0303

- Statistics -
**MathGuru**, Monday, November 5, 2012 at 7:27pmStandard error = √(p1(1-p1)/n1 + p2(1-p2)/n2)

Your data:

n1 = 384

n2 = 432

p1 = 112/384

p2 = 91/432

If you substitute the data into the formula above, you should find standard error to be .0303, which will narrow down your choices. I'll let you determine the pooled value for p.

- Statistics -
**John**, Monday, May 20, 2013 at 11:41pm@MathGuru you're useless. You only solve the obvious and then leave us hanging.

- Statistics -
**Robert**, Monday, March 3, 2014 at 2:46pmI got only love for John. The answer is fate

- Statistics -
**Robert**, Monday, March 3, 2014 at 2:53pm@John I have come from a year later to reply to your concern, to uproot this tyranny that is Math Guru. No longer shall we sit wondering what the other half of the question is. No longer must we be given a formula and have to solve it out. NO LONGER MUST WE SIT THROUGH THIS.

The answer is E.

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