Posted by John on Monday, November 5, 2012 at 9:52am.
Standard error = √(p1(1-p1)/n1 + p2(1-p2)/n2)
Your data:
n1 = 384
n2 = 432
p1 = 112/384
p2 = 91/432
If you substitute the data into the formula above, you should find standard error to be .0303, which will narrow down your choices. I'll let you determine the pooled value for p.
@MathGuru you're useless. You only solve the obvious and then leave us hanging.
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