Posted by **Kathy ** on Monday, November 5, 2012 at 12:21am.

A 50 kg diver leaps off the 20 meter diving board with a velocity of 5 m/s. What is his kinetic energy just before hitting the water?

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**Elena**, Monday, November 5, 2012 at 12:05pm
What is direction of initial velocity?

If v=5 m/s is downward velocity,

PE+KE1=KE2

mgh+mv1²/2 =mv2²/2

v2 =sqrt(2gh+v1²)

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**Nick**, Wednesday, November 18, 2015 at 9:11pm
F=ma

F=50(5)= 250

M(k)=F(k)/F(n)

M(k)=250/(50(9.8))= .51 is the coefficent of his kinetic energy while 250 is his kinetic force.

Probably wrong but that's how I would have done it

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