physics
posted by Kathy on .
A 50 kg diver leaps off the 20 meter diving board with a velocity of 5 m/s. What is his kinetic energy just before hitting the water?

What is direction of initial velocity?
If v=5 m/s is downward velocity,
PE+KE1=KE2
mgh+mv1²/2 =mv2²/2
v2 =sqrt(2gh+v1²) 
F=ma
F=50(5)= 250
M(k)=F(k)/F(n)
M(k)=250/(50(9.8))= .51 is the coefficent of his kinetic energy while 250 is his kinetic force.
Probably wrong but that's how I would have done it