Tuesday
March 28, 2017

Post a New Question

Posted by on .

I am stuck on this question. Any help will be greatly appreciated!

A 0.082 kg solid cylinder with a radius of 1.90 cm, is placed at the top of a 30ยบ inclined plane of height 29.5 cm. If the inclined plane is not frictionless, and the cylinder does roll, determine the speed of the cylinder at the bottom.

  • College Physic - ,

    If the inclined plane is not frictionless, you have to know the coefficient of friction.
    If it is frictionless, then
    PE=KE=KE(transl) +KE(rot)
    mgh= mv²/2 + Iω²/2.
    I=mR²/2, ω=v/R
    mgh= mv²/2 + mR² v²/4 R²=
    = 3mv²/4
    v=sqrt(4gh/3)

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question