College Physic
posted by Jennifer Hill .
I am stuck on this question. Any help will be greatly appreciated!
A 0.082 kg solid cylinder with a radius of 1.90 cm, is placed at the top of a 30ยบ inclined plane of height 29.5 cm. If the inclined plane is not frictionless, and the cylinder does roll, determine the speed of the cylinder at the bottom.

If the inclined plane is not frictionless, you have to know the coefficient of friction.
If it is frictionless, then
PE=KE=KE(transl) +KE(rot)
mgh= mv²/2 + Iω²/2.
I=mR²/2, ω=v/R
mgh= mv²/2 + mR² v²/4 R²=
= 3mv²/4
v=sqrt(4gh/3)