Posted by **Jennifer Hill** on Sunday, November 4, 2012 at 9:34pm.

I am stuck on this question. Any help will be greatly appreciated!

A 0.082 kg solid cylinder with a radius of 1.90 cm, is placed at the top of a 30ยบ inclined plane of height 29.5 cm. If the inclined plane is not frictionless, and the cylinder does roll, determine the speed of the cylinder at the bottom.

- College Physic -
**Elena**, Monday, November 5, 2012 at 12:36pm
If the inclined plane is not frictionless, you have to know the coefficient of friction.

If it is frictionless, then

PE=KE=KE(transl) +KE(rot)

mgh= mv²/2 + Iω²/2.

I=mR²/2, ω=v/R

mgh= mv²/2 + mR² v²/4 R²=

= 3mv²/4

v=sqrt(4gh/3)

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