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Physics

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A ball of mass 0.1 kg is suspended vertically from the ceiling with a "massless" string and
brought to rest. The string is one meter long. When a force of 0.5N is applied 45 deg. below
the horizontal, what will be the magnitude of the resulting angular acceleration of the ball?


How would you go about solving this?

  • Physics - ,

    The torque is M=F•cosα•L.
    The ball is material point => its moment of inertia is
    I=m•L².
    The Newton’s 2 law for rotation
    M=I•ε,
    F•cosα•L= m•L²•ε,
    ε= F•cosα•L/ m•L²=F•cosα /m•L.

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